Logx16=-2 how do you solve this?
the first one is simple, logx16=2 .... x becomes the base and the 2 becomes the exponent there fore x^2=16 and this becomes basic when solving for , put both x^2 and 16 under a radical and x=4
The answer I think is wrong
A negative cant cHange to a positive without doing anything
To solve the equation log(x) 16 = -2, we need to understand the properties of logarithms.
The equation can be rewritten as log base x of 16 = -2.
We know that log base x of a = b can be written as x^b = a. Using this property, we can rewrite the equation as x^(-2) = 16.
Taking the reciprocal of both sides gives us 1/x^2 = 16. Multiplying both sides by x^2, we have 1 = 16x^2.
Dividing both sides by 16, we get x^2 = 1/16.
Taking the square root of both sides gives us x = ±√(1/16).
Simplifying the square root, x = ±(1/4).
Therefore, the solution to the equation log(x) 16 = -2 is x = ±(1/4).