What is the minimum value for P=x-2y over the feasiblity region defined by the constraints shown below?
8
-2
-16
-14
I meant to put D i am just now takeing the test so i hope its right but i think it is so here you go DON'T PUT A OR IT IS WRONG.
answer: -14
Answer is -14!! :))
answer is -14
can someone explain please? I dont want just the answer
To find the minimum value for P = x - 2y over a feasibility region, we need to evaluate the objective function P at each corner point of the feasibility region.
The constraints define a feasibility region with four corner points: (8, 0), (0, -4), (0, -8), and (-7, 0).
1. Evaluate P at each corner point:
P(8, 0) = 8 - 2(0) = 8
P(0, -4) = 0 - 2(-4) = 8
P(0, -8) = 0 - 2(-8) = 16
P(-7, 0) = -7 - 2(0) = -7
2. Compare the values of P at the corner points:
The minimum value for P is -7 which occurs at the corner point (-7, 0).
Therefore, the minimum value for P = x - 2y over the feasibility region is -7, and it occurs at the point (-7, 0).