A 60kg softball player, who is 1.75m tall, performs 12 repetitions of a 140kg squat. If there is a 1m chance from the starting position to the bottom position, how much work is accomplished during the entire set? How much potential energy is stored at the starting position?
To determine the work accomplished during the entire set, we need to calculate the work done for each repetition and then multiply it by the number of repetitions.
First, let's calculate the work done for one repetition:
Work = Force x Distance
The force exerted during a squat is the product of the player's mass and the acceleration due to gravity:
Force = mass x acceleration due to gravity
The distance covered during one repetition is the sum of the distances from the starting position to the bottom position and back to the starting position:
Distance = 2 x height change
Since the height change is given as 1m, the distance covered in one repetition is 2 x 1m = 2m.
The force can be calculated as follows:
Force = mass x acceleration due to gravity
= 60kg x 9.8m/s^2
= 588 N
Now, we can calculate the work done for one repetition:
Work = Force x Distance
= 588 N x 2m
= 1176 Joules
Since the player performs 12 repetitions, we can multiply the work done for one repetition by 12 to find the total work accomplished during the entire set:
Total work = Work per repetition x Number of repetitions
= 1176 Joules x 12
= 14,112 Joules
Next, let's calculate the potential energy stored at the starting position:
Potential energy = mass x gravity x height
Since the height at the starting position is the same as the height change during each repetition (1m), the potential energy at the starting position can be calculated as:
Potential energy = mass x gravity x height
= 60kg x 9.8m/s^2 x 1m
= 588 Joules
Therefore, the total work accomplished during the entire set is 14,112 Joules, and the potential energy stored at the starting position is 588 Joules.