a feather is dropped on the moon from a height of 1.4 meters.the acceleration of the moon is 1.67 m/s determine the time for the feather to fall on the surface of
the moon
See previous post.
90seconds
To determine the time it takes for the feather to fall on the surface of the moon, you can use the kinematic equation for linear motion:
s = ut + (1/2)at^2
Where:
s = distance or height (1.4 meters in this case)
u = initial velocity (0, since the feather is dropped and not given an initial velocity)
a = acceleration (1.67 m/s)
t = time
In this case, the equation becomes:
1.4 = 0 * t + (1/2) * 1.67 * t^2
Simplifying the equation:
1.4 = (1/2) * 1.67 * t^2
To solve for t, we can rearrange the equation:
t^2 = (2 * 1.4) / 1.67
t^2 = 2.80 / 1.67
t^2 ≈ 1.6766
Taking the square root of both sides:
t ≈ √1.6766
t ≈ 1.295 seconds
Therefore, it takes approximately 1.295 seconds for the feather to fall on the surface of the moon.