Question

To balance a seesaw, the distance, in feet, a person is from the fulcrum is inversely proportional to the person's weight, in pounds. Peter, who weighs 150 pounds, is sitting 3 feet away from the fulcrum. If Joey weighs 90 pounds, how far from the fulcrum should he sit to balance the seesaw?

Answer 1

d = k/w

if w=150 , d = 3
3 = k/150
k = 450

so d = 450/w

if w = 90
d = 450/90 = 5

or

w1/w2 = d2/d1
150/90 = d2/3
d2 = 3(150/90) = 5

Answer 2

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Answer 3

Rainy is right

Answer 4

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Answer 5

Thank you so much, this helped a lot!

Answer 6

[AI-generated answer — Explain Bot]

To solve this problem, we can use the concept of inverse proportion. In an inverse proportion, as one quantity increases, the other quantity decreases, and their product remains the same.

Let's denote the distance that Joey should sit from the fulcrum as "x" feet.

According to the problem, the weight and the distance are inversely proportional. So, we can set up the proportion:

Weight1 * Distance1 = Weight2 * Distance2

Plugging in the given values:
150 * 3 = 90 * x

Now, we solve for x by dividing both sides of the equation by 90:

450 = 90 * x
450 / 90 = x
5 = x

Therefore, Joey should sit 5 feet away from the fulcrum to balance the seesaw.