Write a balanced equation for the following:
aqueous barium chloride reacts with aqueous sodium chromate to form aqueous sodium chloride plus solid barium chromate.
BaCl2 + Na2CrO4--->2NaCl + BaCrO4
Sure! Here's a balanced equation for the reaction:
BaCl2(aq) + Na2CrO4(aq) → 2 NaCl(aq) + BaCrO4(s)
And remember, this reaction is as balanced as a clown walking a tightrope while juggling rubber chickens!
The balanced equation for the reaction can be written as follows:
BaCl2(aq) + Na2CrO4(aq) → 2NaCl(aq) + BaCrO4(s)
To write a balanced equation, we need to ensure that there is an equal number of atoms of each element on both sides of the equation.
The given equation is:
Aqueous barium chloride (BaCl2) + Aqueous sodium chromate (Na2CrO4) → Aqueous sodium chloride (NaCl) + Solid barium chromate (BaCrO4)
Now, let's balance the equation step-by-step:
First, count the number of atoms for each element on both sides of the equation:
Ba: 1 on the left, 1 on the right
Cl: 2 on the left, 1 on the right
Na: 2 on the left, 1 on the right
Cr: 1 on the left, 1 on the right
O: 4 on the left, 4 on the right
The atoms that are not balanced are Cl and Na. To balance them, we need to multiply the compounds by appropriate coefficients:
BaCl2 + Na2CrO4 → 2NaCl + BaCrO4
Now, let's recheck the number of atoms for each element:
Ba: 1 on the left, 1 on the right
Cl: 2 on the left, 2 on the right
Na: 2 on the left, 2 on the right
Cr: 1 on the left, 1 on the right
O: 4 on the left, 4 on the right
Now the equation is balanced!