How much concentrated solution would you take to prepare 2.80L of 0.475M HCl by mixing with water?
What concentrated acid? 12M
If 12 M, you are diluted 12/.475 times, 25.26 times.
so you need 1 part conc acid, then 24.26 parts water.
one part is 2800ml/25.26 = 110.8 ml
To determine how much concentrated solution is needed, we can use the formula:
M1V1 = M2V2
Where:
M1 = initial concentration of the solution
V1 = initial volume of the solution
M2 = final concentration of the solution
V2 = final volume of the solution
In this case, we are preparing a 0.475M HCl solution with a final volume of 2.80L. The concentrated solution is assumed to be 100% HCl (which means it has a concentration of 1M).
Let's plug the values into the formula:
(1M)(V1) = (0.475M)(2.80L)
Now, we can solve for V1:
V1 = (0.475M)(2.80L) / (1M)
V1 ≈ 1.33L
Therefore, approximately 1.33L of the concentrated HCl solution needs to be taken and mixed with water to prepare 2.80L of a 0.475M HCl solution.