find the ordered pair of
a+8b=9
a+3b=-1
(-7,2)
subtracting the two
5b=10
b =5
a=9-8b==>9-8(5)
=-31
why do i find this confusiong
a+8b=11
a+2b=-1
subtract the second from the first:
(1-1)a + (8-2)b = 11-(-1)
0a+6b = 12
b=2
so, a = 11-8b = -5
or, a = -1 - 2b = -5
sorry
b=2 and a=-7
To find the ordered pair of (a, b) for the given system of equations:
1. Write down the two equations:
a + 8b = 9 ...(Equation 1)
a + 3b = -1 ...(Equation 2)
2. Solve one equation for one variable. Let's solve Equation 2 for a:
a = -1 - 3b
3. Substitute the value of a into the other equation (Equation 1):
-1 - 3b + 8b = 9
4. Simplify and combine like terms:
5b - 1 = 9
5. Solve for b:
5b = 10
b = 2
6. Substitute the value of b into the previously solved equation (Equation 2) to find a:
a = -1 - 3(2)
a = -1 - 6
a = -7
Therefore, the ordered pair (a, b) is (-7, 2).