Divide
{6x^3y^6} / {24x^4y^3}
_______ _________
{16a^4b^2} {14a^7b}
6x^3y^6/24x^4y^3 = y^3/4x
16a^4b^2 * 14a^7b = 224a^9b^3
so, we wind up with
y^3 / (896 a^9 b^3 x)
odd problem
If there was supposed to be a division in the denominator, adjust accordingly.
To divide two fractions, we need to follow these steps:
Step 1: Simplify both the numerator and denominator separately.
Let's simplify the numerator first:
6x^3y^6 can be written as (2 * 3 * x * x * x * y * y * y * y * y * y).
Now let's simplify the denominator:
24x^4y^3 can be written as (2 * 2 * 2 * 3 * x * x * x * x * y * y * y).
Step 2: Cancel out any common factors between the numerator and denominator.
As we can see, there are common factors of 2, 3, x, and y in both the numerator and denominator.
After canceling out the common factors, we are left with:
Numerator: (y^3 * y^3 * y^3 * y^3)
Denominator: (2 * x * x * y * y * y).
Step 3: Simplify the resulting expression.
Now that we have canceled out the common factors, we can simplify further by combining the remaining terms:
Numerator: y^12
Denominator: (2xy^3)
Step 4: Write the simplified fraction.
Finally, we can write the simplified fraction by placing the numerator over the denominator:
y^12 / (2xy^3)
To answer the question, the division of (6x^3y^6) / (24x^4y^3) is y^12 / (2xy^3).