a pile of fifty $1, $5 and $10 bills is worth $237. The number of $5 bills is twice as many as $10 bills.How many
$1 bills in the pile?
To find the number of $1 bills in the pile, let's create equations based on the given information.
Let's assume the number of $10 bills is x.
According to the given information, the number of $5 bills is twice as many as $10 bills. Therefore, the number of $5 bills would be 2x.
Now, let's calculate the total value of the bills. We know that each $10 bill is worth $10, each $5 bill is worth $5, and each $1 bill is worth $1.
The total value of the $10 bills would be 10x.
The total value of the $5 bills would be 5(2x) = 10x.
The total value of the $1 bills cannot be determined yet.
Now, we can set up an equation based on the given information:
10x + 10x + y = 237
Here, y represents the total value of the $1 bills.
To solve for x and y, we need another equation. Let's use the fact that there are 50 total bills in the pile:
x + 2x + y = 50
Now, we have a system of equations:
10x + 10x + y = 237
x + 2x + y = 50
Simplifying the equations, we get:
20x + y = 237
3x + y = 50
Now, we can solve this system of equations using substitution or elimination to find the values of x and y.