A capacitor has a charge of 5 µC when charged by a potential difference of 1.5 V. What is the capacitance of the capacitor?
C=q/U=5•10⁻⁶/1.5=3.33•10⁻⁶ F
To find the capacitance of the capacitor, you can use the formula:
C = Q / V
where C is the capacitance, Q is the charge, and V is the potential difference.
In this case, the charge is given as 5 µC (microcoulombs) and the potential difference is 1.5 V.
To solve for capacitance, plug in these values into the formula:
C = 5 µC / 1.5 V
Now, let's convert the charge from microcoulombs to coulombs, as it's the standard unit:
1 µC = 1 × 10^-6 C
So, 5 µC = 5 × 10^-6 C
Now we have:
C = (5 × 10^-6 C) / 1.5 V
Divide the numerator by the denominator:
C = 3.33 × 10^-6 F
Therefore, the capacitance of the capacitor is approximately 3.33 µF (microfarads).