Using the equation N2 + 3H2 yields ==> 2NH3 , determine how many grams of ammonia will be produced when 233 grams of hydrogen is consume
To determine how many grams of ammonia will be produced when 233 grams of hydrogen is consumed, we need to first calculate the amount of hydrogen in moles using its molar mass, and then use the stoichiometry of the balanced chemical equation to find the amount of ammonia produced.
Step 1: Calculate the moles of hydrogen (H2):
Molar mass of H2 = 2.016 g/mol (1.008 g/mol per hydrogen atom)
Moles of H2 = mass of H2 / molar mass of H2
= 233 g / 2.016 g/mol
≈ 115.62 mol
Step 2: Use the stoichiometry of the balanced chemical equation to find the moles of ammonia (NH3) produced:
From the balanced equation: N2 + 3H2 → 2NH3
We can see that 3 moles of hydrogen react to produce 2 moles of ammonia.
Moles of NH3 = (moles of H2 / 3) * (2 moles of NH3 / 3 moles of H2)
= (115.62 mol / 3) * (2 mol / 3 mol)
≈ 38.54 mol
Step 3: Convert moles of NH3 to grams:
Molar mass of NH3 = 17.031 g/mol (14.007 g/mol per nitrogen atom + 1.008 g/mol per hydrogen atom)
Grams of NH3 = moles of NH3 * molar mass of NH3
= 38.54 mol * 17.031 g/mol
≈ 656.63 g
Therefore, approximately 656.63 grams of ammonia will be produced when 233 grams of hydrogen is consumed.