How many moles of aluminum are needed to react completely with 1.2 mol of FeO?
2Al(s) + 3FeO(s)-- 3Fe(s) + Al2O3(s)
0.8 mol
To determine the number of moles of aluminum needed to react completely with 1.2 mol of FeO, we need to use the balanced chemical equation for the reaction.
The balanced equation shows that the stoichiometric ratio between aluminum (Al) and FeO is 2:3. This means that for every 2 moles of aluminum, 3 moles of FeO are required.
Given that there are 1.2 mol of FeO, we can set up a ratio and solve for the number of moles of aluminum:
(2 mol Al / 3 mol FeO) * 1.2 mol FeO = 0.8 mol Al
Therefore, 0.8 moles of aluminum are needed to react completely with 1.2 mol of FeO.