A box of 5 kg mass slides horizontally on the floor for along a distance 9m in 3s due to a constant force. The magnitude of the constant force is ...
Is there friction? Is it accelerating from an initial speed of zero? More information is needed.
If it starts out with zero velocity, it acquires a final speed of 6 m/s. (Twice the average speed).
If there is no friction, final KE = Work done.
(1/2)M*Vfinal^2 = Force*Distance
Solve for the force
To find the magnitude of the constant force acting on the box, we need to use Newton's second law of motion, which states that force (F) equals mass (m) multiplied by acceleration (a). In this case, the acceleration can be calculated using the formula:
a = (final velocity - initial velocity) / time
Since the box is initially at rest and comes to a final velocity, we can assume the initial velocity is zero. The final velocity can be calculated using the formula:
v = distance / time
Plugging in the values given, we get:
v = 9m / 3s = 3 m/s
Now we can calculate the acceleration:
a = (3 m/s - 0) / 3s = 1 m/s^2
Finally, we can find the magnitude of the force by multiplying the mass by the acceleration:
F = m * a = 5 kg * 1 m/s^2 = 5 N
Therefore, the magnitude of the constant force acting on the box is 5 Newtons.