# Hi, I need some help with this problem:

The density of ice is 920 kg/m3, and that of sea water is 1030 kg/m3. What fraction of the total volume of an iceberg is exposed?

I took the density of the iceberg divided by the density of the water and multiplied this by 100, but this did not give me the correct answer.

I don't know why you mulitiplied by 100, however...

Consider 1000 kg of ice. It has a volume of 1000/920 m^3.

To meed the bouyance of this, 1000 kg of sea water has to be displaced> a volume of 1000/1030 m^3.

How much is exposed: the difference..

exposed= 1000/920 - 1000/1030

or 1000(1030 - 920)/920*1030

fraction exposed = exposed/total ice volume

= 1000(1030 - 920)/920*1030*(1000/920)

= (1030 - 920) / *1030

check that.

## i do not know the answer either

## I have trouble with these kind of problems. I don't know the answer either. Sorry wish I could help!!!!

## To find the fraction of the total volume of an iceberg that is exposed, you first need to understand the concept of buoyancy.

To calculate the exposed volume, you can compare the volume of the ice with the volume of water it displaces. The volume of ice can be calculated by dividing the mass of the ice by its density. Similarly, the volume of water displaced can be calculated by dividing the mass of the water by its density.

Let's take 1000 kg of ice as an example. The volume of this ice would be 1000 kg divided by 920 kg/m^3, which is approximately 1.087 m^3.

To meet the buoyancy of the ice, 1000 kg of sea water would have to be displaced. So, the volume of water displaced would be 1000 kg divided by 1030 kg/m^3, which is approximately 0.9709 m^3.

The exposed volume of the iceberg would be the difference between the volume of the ice and the volume of water displaced. In this case, it would be 1.087 m^3 minus 0.9709 m^3, which is approximately 0.1161 m^3.

To find the fraction of the total volume that is exposed, you divide the exposed volume by the total volume of the ice. In this case, it would be 0.1161 m^3 divided by 1.087 m^3, which is approximately 0.1069.

So, the fraction of the total volume of the iceberg that is exposed is approximately 0.1069, or about 10.7%.