# Ok. so i'm supposed to find the coordinates of a line using the slope intercept method but i don't understand it!!! can some one PLEEAASE help me? also i'm supposed to graph a line using the same method and they give me the coordinates oly its in an equation form that i need to solve only i don't know how. heres the coordinates. please help me unscramble it all!

y= 3/2*(x) + 3

2y= -(x) + 2

oh, um, whoops, i kinda forgot one of the problems. its the one where i'm supposed to find the coordinates of a line. i know the coordinates, but i don't know how to how to get them. here they are.

y= -(x) + 2

PLEASE HURRY!!!! thanx. :-)

## Sure, I can help you with both problems. Let's start with finding the coordinates of a line using the slope-intercept method for the equation y = mx + b.

For the first equation y = (3/2)x + 3, we can identify the slope (m) and the y-intercept (b). The coefficient of x, which is 3/2, represents the slope, and the constant term 3 represents the y-intercept.

Now, to find the coordinates, we usually need two points on the line. One way to do this is to set x=0 and solve for y, and vice versa. Let's find two points on the line using this method:

1. When x = 0:

Substitute x = 0 into the equation:

y = (3/2)(0) + 3

y = 0 + 3

y = 3

Therefore, one point is (0,3).

2. When y = 0:

Substitute y = 0 into the equation:

0 = (3/2)x + 3

(3/2)x = -3

Multiply both sides by 2/3 to isolate x:

x = -3 * 2/3 = -2

Therefore, another point is (-2,0).

Hence, the coordinates of the line y = (3/2)x + 3 are (0,3) and (-2,0).

Now, let's move on to graphing a line using the slope-intercept method.

For the equation 2y = -x + 2, we need to rewrite it in the y = mx + b form.

To do this, divide both sides of the equation by 2 to isolate y:

(2y)/2 = (-x + 2)/2

y = (-1/2)x + 1

Now, let's find two points on this line:

1. When x = 0:

Substitute x = 0 into the equation:

y = (-1/2)(0) + 1

y = 0 + 1

y = 1

Therefore, one point is (0,1).

2. When y = 0:

Substitute y = 0 into the equation:

0 = (-1/2)x + 1

(-1/2)x = -1

Multiply both sides by -2/1 to isolate x:

x = -1 * (-2/1) = 2

Therefore, another point is (2,0).

Therefore, the coordinates of the line y = (-1/2)x + 1 are (0,1) and (2,0).

I hope this explanation helps you understand how to find the coordinates of a line using the slope-intercept method and how to graph a line. Let me know if you have any further questions!