# Question: Calculate the frequency of the AA, Aa, and aa genotypes after one generation if the initial population consists of 0.2 AA, 0.6 Aa, and 0.2 aa.

What I have done is:

P = (0.2)+(0.5)(0.6)= 0.50

q = 1-p = 1 - 0.50 = 0.50

Can someone check my answer plz.

Looks correct. There are good google articles under genotype probabilities

8 months ago

## To calculate the frequency of the AA, Aa, and aa genotypes after one generation, you can use the Hardy-Weinberg Equilibrium equation. This equation allows you to determine genotype frequencies based on the allele frequencies in the population.

The Hardy-Weinberg equation states that p^2 + 2pq + q^2 = 1, where p represents the frequency of the dominant allele (in this case, A) and q represents the frequency of the recessive allele (in this case, a).

In your case, you have already determined the initial allele frequencies using the given population information:
p = 0.2 + 0.5(0.6) = 0.5 (frequency of the dominant allele A)
q = 1 - p = 1 - 0.5 = 0.5 (frequency of the recessive allele a)

Now, let's calculate the genotype frequencies after one generation using the values of p and q obtained:

Frequency of AA genotype (p^2):
AA genotype frequency = p^2 = 0.5^2 = 0.25 (or 25%)

Frequency of Aa genotype (2pq):
Aa genotype frequency = 2pq = 2(0.5)(0.5) = 0.5 (or 50%)

Frequency of aa genotype (q^2):
aa genotype frequency = q^2 = 0.5^2 = 0.25 (or 25%)

So, after one generation, the frequencies of the AA, Aa, and aa genotypes in the population will be 25%, 50%, and 25%, respectively.