# I need some help with this problem.

A number is less than the sum of twice its opposite and five. Find the number.

If by "its opposite" you mean the same number with opposite sign, then if you let x be that unknown number

x < -2x + 5
You can add 2x to both sides and keep the direction of the < the same.
3x < 5
You can divide both sides by 3 and keep the direction of the < the same.
x < 5/3

I'm not sure what you mean by "opposite." If you mean inverse, this would be your formula.

X < 2(1/X) + 5 or 2(1/X + 5)

Even assuming that it is the inverse, your description is not clear enough to know which of the above applies.

I hope this helps. If not, clarify your meaning in another post, and we will do our best to help you. Thanks for asking.

8 months ago

## To solve the problem, let's break it down step by step.

1. The problem states that a number is less than the sum of twice its opposite and five.
- Let's assume the unknown number is represented as x.

2. The term "opposite" refers to the same number with the opposite sign.
- So, the opposite of x would be -x.

3. According to the problem, the number x is less than the sum of twice its opposite (-2x) and five.
- This can be represented as: x < -2x + 5.

4. Now, let's solve the inequality to find the value of x.
- To get rid of the -2x on the right side of the inequality, we can add 2x to both sides, while keeping the direction of the inequality the same:
x + 2x < -2x + 5 + 2x.
Simplifying this, we get:
3x < 5.

5. Finally, to isolate x, we divide both sides of the inequality by 3, while keeping the direction of the inequality the same:
(3x)/3 < 5/3.
Simplifying this, we get:
x < 5/3.

Therefore, the solution to the problem is x < 5/3. This means that any number which is less than 5/3 will satisfy the given condition.

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