# Question: Calculate the frequency of the AA, Aa, and aa genotypes after one generation if the initial population consists of 0.2 AA, 0.6 Aa, and 0.2 aa.

What I have done is:

P = (0.2)+(0.5)(0.6)= 0.50

q = 1-p = 1 - 0.50 = 0.50

Can someone check my answer plz.

8 months ago

## To calculate the frequency of genotypes after one generation, you need to use the Hardy-Weinberg principle formula:

p^2 + 2pq + q^2 = 1

where:
p^2 represents the frequency of the homozygous dominant (AA) genotype,
2pq represents the frequency of the heterozygous (Aa) genotype,
q^2 represents the frequency of the homozygous recessive (aa) genotype, and
1 represents the total frequency of all genotypes combined.

Let's calculate the frequencies based on the information you provided:

P = 0.2
q = 0.5 (since q = 1 - p)

To find p^2, we square the value of p:
p^2 = (0.2)^2 = 0.04

To find q^2, we square the value of q:
q^2 = (0.5)^2 = 0.25

To find 2pq, multiply 2 by the values of p and q:
2pq = 2 * (0.2) * (0.5) = 0.2

Now let's check if the frequencies add up to 1:
0.04 + 0.2 + 0.25 = 0.49

It seems there might be an error in your calculations. The sum of the frequencies is not equal to 1. However, to confirm this, we need the remaining information on how you derived the value of 0.5 for p.

Please provide the complete equation or the specific explanation you used to calculate the frequency of p.

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