How can you calculate activation energy in (kj/mol)?
When all that is given is inverse temperature, and natural log reaction constant?
Inverse: 1/278 for Kelvin temp, 1/308
Natural Log Reaction Rate Constant:
4.3
5.5
When all that is given is inverse temperature, and natural log reaction constant?
Inverse: 1/278 for Kelvin temp, 1/308
Natural Log Reaction Rate Constant:
4.3
5.5