Can anyone help me with this questioin pleasee?

Describe the orientation and relative energy levels of sp2 and sp3 orbitals with respect to unhyberdized orbitals (1s, 2s, 2px, 2py, 2pz orbitals)

1s and 2s are spherical.
2px, 2py, and 2pz are at 90o to each other (mutually perpendicular) along the x, y, and z spatial axes. I'm sure there are pictures in your text or you can find some on the web. The hybidized sp2 orbitals are trigonal planar and the sp3 hybridized orbitals are tetrahedral.

http://www.mhhe.com/physsci/chemistry/essentialchemistry/flash/hybrv18.swf

(Broken Link Removed)

what is hybridization?

i want an explain with drawing for hybridization in pocl3 and h2s and sf4

i want an explain with drawing for hybridization in pocl3 and h2s and sf4

rbovmehzk vajzerc rbovmehzk vajzerc answered
15 years ago

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tina tina answered
13 years ago

how to calculate the hybridisation of a molecule in simple and detailed way

Explain Bot Explain Bot answered
7 months ago

Hybridization is a concept in chemistry that explains the mixing of atomic orbitals to form new hybrid orbitals with different shapes and energies. These hybrid orbitals are then used to describe the bonding in molecules.

To understand the hybridization in PCl3 (phosphorus trichloride) and H2S (hydrogen sulfide), we need to look at the central atom and the surrounding atoms.

- PCl3:
In PCl3, phosphorus is the central atom surrounded by three chlorine atoms. Phosphorus has five valence electrons in its ground state: 3s^2 3p^3. To form bonds with the three chlorine atoms, phosphorus undergoes sp3 hybridization. This means that one 3s orbital and three 3p orbitals (3px, 3py, and 3pz) mix together to form four sp3 hybrid orbitals. These sp3 orbitals are arranged in a tetrahedral geometry around the phosphorus atom, with approximately 109.5° bond angles.

To represent the hybridization in PCl3, we can use a drawing like this:
Cl
|
Cl-P-Cl
|
Cl

- H2S:
In H2S, sulfur is the central atom bonded to two hydrogen atoms. Sulfur has six valence electrons in its ground state: 3s^2 3p^4. To bond with the two hydrogen atoms, sulfur undergoes sp3 hybridization. One 3s orbital and three 3p orbitals (3px, 3py, and 3pz) mix together to form four sp3 hybrid orbitals. These sp3 orbitals are arranged in a tetrahedral geometry around the sulfur atom, with bond angles of approximately 109.5°.

To represent the hybridization in H2S, we can use a drawing like this:
H
|
H-S-H

- SF4:
In SF4, sulfur is the central atom bonded to four fluorine atoms. Sulfur has six valence electrons in its ground state: 3s^2 3p^4. To bond with the four fluorine atoms, sulfur undergoes sp3d hybridization. One 3s orbital, three 3p orbitals (3px, 3py, and 3pz), and one 3d orbital (3dz^2) mix together to form five sp3d hybrid orbitals. These sp3d orbitals are arranged in a trigonal bipyramidal geometry around the sulfur atom, with bond angles of approximately 90° and 120°.

To represent the hybridization in SF4, we can use a drawing like this:
F F
\ /
S
/ \
F F

I hope this explanation and the drawings help you understand the hybridization in PCl3, H2S, and SF4.

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