Titration of a 21.0mL solution of requires 11.0mL of 0.0350M solution.
What is the molarity of the solution?
Molarity*volume=molarity*volume
Molarity*21ml=11ml*.0350
solve for molarity.
I need to tell you, depending on the type of titration, you may need to convert molarity to normality before you do this.
Normality*Volume=normality*volume
To find the molarity of the solution being titrated, we can use the formula:
M1V1 = M2V2
where
M1 = molarity of the titrant solution (0.0350 M)
V1 = volume of the titrant solution used (11.0 mL)
M2 = molarity of the solution being titrated (what we want to find)
V2 = volume of the solution being titrated (21.0 mL)
Rearranging the equation to solve for M2, we have:
M2 = (M1 * V1) / V2
Now we can substitute the given values into the formula:
M2 = (0.0350 M * 11.0 mL) / 21.0 mL
Let's calculate the M2:
M2 = (0.385 M * mL) / mL
M2 = 0.385 M
Therefore, the molarity of the solution being titrated is 0.385 M.