Calculate the number of grams of solute in 250.0 mL of 0.149 M KOH.
Well, let me put on my glasses to give you a mathematical answer... Oh wait, I'm a bot, I don't have eyes! Nonetheless, I can still calculate it for you.
To calculate the number of grams of solute, in this case, KOH, we need to use the equation:
grams of solute = Molarity × Volume (in Liters) × Molar mass
In this case, the molarity is given as 0.149 M KOH and the volume is given as 250.0 mL. We need to convert the volume to liters, as the unit liters is needed in the formula.
So, 250.0 mL = 250.0 mL ÷ 1000 = 0.250 L
Now that we have the values, we need the molar mass of KOH. The molar mass of potassium (K) is 39.1 g/mol, the molar mass of oxygen (O) is 16.0 g/mol, and the molar mass of hydrogen (H) is 1.0 g/mol. Adding them up, we get:
Molar mass of KOH = 39.1 g/mol + 16.0 g/mol + 1.0 g/mol = 56.1 g/mol
Now we can calculate the grams of solute:
grams of solute = 0.149 M × 0.250 L × 56.1 g/mol = 2.096 g
Therefore, there are approximately 2.096 grams of KOH in 250.0 mL of 0.149 M KOH.
To calculate the number of grams of solute in a solution, you need to use the formula:
grams of solute = concentration (Molarity) × volume (L) × molar mass (g/mol)
Given:
Concentration (Molarity) = 0.149 M
Volume = 250.0 mL (which needs to be converted to liters)
Molar mass of KOH = 56.11 g/mol
First, convert the volume from mL to L:
250.0 mL ÷ 1000 mL/L = 0.250 L
Now, plug the values into the formula:
Grams of solute = 0.149 M × 0.250 L × 56.11 g/mol
Calculating this expression will give you the number of grams of solute in the solution.
To calculate the number of grams of solute in a given solution, we need to use the equation:
moles of solute = molarity × volume of solution (in liters)
First, let's convert the volume of the solution from milliliters to liters:
250.0 mL ÷ 1000 = 0.250 L
Using the given molarity of 0.149 M and the converted volume of 0.250 L, we can now calculate the number of moles of solute:
moles of solute = 0.149 M × 0.250 L = 0.03725 moles
Now, to calculate the number of grams of solute, we need to use the molar mass of KOH. The molar mass of KOH is 56.11 g/mol.
grams of solute = moles of solute × molar mass of KOH
= 0.03725 moles × 56.11 g/mol
≈ 2.09 grams
Therefore, there are approximately 2.09 grams of solute (KOH) in 250.0 mL of 0.149 M KOH solution.
How many moles do you have? That's M x L = ?
Then g = mols x molar mass.