Records from buzz's sawmill show that workers have a 0.02 probability of losing an arm and a 0.03 probability of losing a leg in a year.
What is the probability that a worker does not lose an arm?
What is the probability that worker does not lose and arm or leg?
Pr(NOT arm)=.98
Pr(NOT arm NOR leg)= 1-Pr(leg)-pr(arm)
oops.
Pr(NOT arm NOR leg)=1-Pr(arm or leg)
= 1-Pr(arm)-Pr(leg)+pr(arm AND leg)
= 1-.02-.03+.02*.03
To find the probability that a worker does not lose an arm in a year, we can subtract the probability of losing an arm from 1.
Probability of not losing an arm = 1 - Probability of losing an arm
Given that the probability of losing an arm is 0.02, the probability of not losing an arm would be:
Probability of not losing an arm = 1 - 0.02 = 0.98
So, the probability that a worker does not lose an arm is 0.98.
To find the probability that a worker does not lose an arm or leg, we can subtract the probability of losing an arm and the probability of losing a leg from 1.
Probability of not losing an arm or leg = 1 - Probability of losing an arm - Probability of losing a leg
Given that the probability of losing an arm is 0.02 and the probability of losing a leg is 0.03, the probability of not losing an arm or leg would be:
Probability of not losing an arm or leg = 1 - 0.02 - 0.03 = 0.95
So, the probability that a worker does not lose an arm or leg is 0.95.