# 0.0100kg particles have been glued to a rod of Length L=6.00cm and negligible mass and can rotate around a perpendicular axis through point O at one end. How much work is required to change the rotational rate (a) from 0-20.0 rad/s, (b) from 20.0 rad/s to 40.0 rad/s, and (c) from 40.0 rad/s to 60 rad/s? (d) what is the slope of a plot of the assembly's kinetic energy in joules versus the square of its rotational rate (in radians-squared per second squared)?

## To find the work required to change the rotational rate, we need to use the formula for rotational kinetic energy. The formula for rotational kinetic energy is given by:

KE = (1/2) * I * ω^2

Where:

KE is the kinetic energy,

I is the moment of inertia, and

ω is the angular velocity.

To calculate the work required, we need to subtract the initial kinetic energy from the final kinetic energy and multiply it by -1 (since the work done is against the rotation). The formula for work is given by:

Work = -ΔKE = -(KE_final - KE_initial)

(a) To find the work required to change the rotational rate from 0 to 20.0 rad/s, we need to calculate the initial and final kinetic energies.

Initially, the rotational rate is 0 rad/s, so the initial kinetic energy is 0.

When the rotational rate changes to 20.0 rad/s, we can calculate the final kinetic energy using the given data. Assuming the particles are glued along the rod at perpendicular distances r from the axis of rotation, we can express the moment of inertia I as:

I = Σ m_i * r_i^2

Where:

Σ represents the sum of each particle's contribution to the moment of inertia,

m_i is the mass of each particle, and

r_i is the perpendicular distance of each particle from the axis of rotation.

Since all the particles are glued to the rod, the perpendicular distances r_i will be the same for all particles. Given that the mass of each particle is 0.0100 kg and the length of the rod is 6.00 cm, we can substitute these values into the moment of inertia equation. Assuming the rod is uniform, we can write:

I = m * L^2 / 3

Where:

m is the total mass glued to the rod, and

L is the length of the rod.

Substituting the values, we have:

I = (0.0100 kg) * (0.0600 m)^2 / 3

Calculate this value to find the moment of inertia, I.

Once you have calculated the moment of inertia, substitute the values into the formula for rotational kinetic energy:

KE_final = (1/2) * I * ω^2

Now, you can calculate the final kinetic energy.

Finally, substitute the initial and final kinetic energies into the formula for work to find the required work.

Repeat the above steps for parts (b), (c), and (d), using the given values for the different rotational rates and follow the same procedure to calculate the required work.

To find the slope of the plot of the assembly's kinetic energy in joules versus the square of its rotational rate, you need to plot the kinetic energy on the y-axis and the square of the rotational rate on the x-axis. Then, calculate the slope of the best-fit line for the data points. This can be done using linear regression techniques or by finding the difference in kinetic energy divided by the difference in the square of the rotational rate between two points on the plot.

I hope these explanations help you solve the problem!