what will be the final temperature of a system in which 150.0g of water at 5.0 degrees C are added to 1.00L of water at 90.5 degrees C?

DrBob222 DrBob222 answered

heat absorbed by cool water + heat lost by warm water = 0

[mass cool water x specific heat water x (Tfinal-Tinitial)] + [mass warm water x specific heat water x (Tfinal-Tinitial)] = 0
Solve for Tfinal.

RoseBud RoseBud answered

150.0g x 4.184x(85.5)= 53659.80

+
1000ml x 4.184x 5 = 20920

74579.80 / 4.184=

I DON'T GET IT!

DrBob222 DrBob222 answered

You didn't substitute correctly.

It should be
[150.0 x 4.183 x (Tf-5)] + [1000 x 4.184 x (Tf-90.5)] = 0 and you solve for Tf.

DrBob222 DrBob222 answered

BTW, thanks for showing your work. That makes it easy to spot what's wrong.

DrBob222 DrBob222 answered

You should get an answer that's about 79 C for Tfinal.

RoseBud RoseBud answered

This makes sense. Thank you so much. This a great website. I don't just want someone to tell me the answer....I want to know how to figure it out. Thanks.

Anonymous Anonymous answered

Verve the vrbt