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# what will be the final temperature of a system in which 150.0g of water at 5.0 degrees C are added to 1.00L of water at 90.5 degrees C?

DrBob222
answered

## heat absorbed by cool water + heat lost by warm water = 0

[mass cool water x specific heat water x (Tfinal-Tinitial)] + [mass warm water x specific heat water x (Tfinal-Tinitial)] = 0

Solve for Tfinal.

RoseBud
answered

## 150.0g x 4.184x(85.5)= 53659.80

+

1000ml x 4.184x 5 = 20920

74579.80 / 4.184=

I DON'T GET IT!

DrBob222
answered

## You didn't substitute correctly.

It should be

[150.0 x 4.183 x (Tf-5)] + [1000 x 4.184 x (Tf-90.5)] = 0 and you solve for Tf.

DrBob222
answered

## BTW, thanks for showing your work. That makes it easy to spot what's wrong.

DrBob222
answered

## You should get an answer that's about 79 C for Tfinal.

RoseBud
answered

## This makes sense. Thank you so much. This a great website. I don't just want someone to tell me the answer....I want to know how to figure it out. Thanks.

Anonymous
answered