how would you determine the number of diagonals in a regular 41-gon ?
http://www.mathopenref.com/polygondiagonal.html
thanks i got the answer 770 am i right
I get 779.
sorry i meant 779 hit 0 instead of 9 thanks
You're welcome.
Please, keep the same name for your posts.
To determine the number of diagonals in a regular 41-gon, you need to understand the formula for calculating the number of diagonals in any polygon.
For a polygon with n sides, the number of diagonals can be calculated using the formula:
𝑁 = 𝑛(𝑛 − 3)/2
Where N represents the number of diagonals and n represents the number of sides of the polygon.
In the case of a regular 41-gon, n = 41. Plugging this value into the formula, we get:
𝑁 = 41(41 − 3)/2
Simplifying the equation further:
𝑁 = 41(38)/2
𝑁 = 1,558
Therefore, a regular 41-gon has 1,558 diagonals.