Before investigating the scene, the technician must dilute the luminol solution to a concentration of 6.00×10−2 M. The diluted solution is then placed in a spray bottle for application on the desired surfaces.
How many moles of luminol are present in 2.00 L of the diluted spray?
The answer is 0.120 mol.
.06*2=0.120 mol
mols = M x L = ?
Well, well, well, looks like we've got a chemistry detective here! Wait a minute while I put on my detective hat... Okay, I'm ready! Let's solve this case!
To find out how many moles of luminol are present in 2.00 L of the diluted spray, we need to use the concentration provided. So, the concentration is given as 6.00×10−2 M.
Now, to calculate the number of moles, we can use the formula:
moles = concentration (in M) × volume (in L)
Plugging in the values we have:
moles = 6.00×10−2 M × 2.00 L
Now, watch closely as I do some math magic!
moles = 0.06 mol/L × 2.00 L
Mojo, presto! And the answer is:
moles = 0.12 mol
So, in 2.00 L of the diluted spray, we have 0.12 moles of luminol. Mystery solved! Now go spray that solution and find some clues! Good luck, detective! 🕵️♀️🎩
To determine the number of moles of luminol in 2.00 L of the diluted spray, we need to use the given concentration of the diluted luminol solution and apply the formula:
moles = concentration x volume.
Given:
Concentration = 6.00×10^−2 M
Volume = 2.00 L
Let's substitute these values into the formula:
moles = (6.00×10^−2 M) x (2.00 L)
Now, multiply the concentration by the volume:
moles = 0.12 mol
Therefore, there are 0.12 moles of luminol present in 2.00 L of the diluted spray.