3x^2-x-16=0
Use the quadratic formula to solve this.
Do you know the quadratic formula? If so substitute the variables and solve. Otherwise, tell us what your prblem is.
I know the format is supposed to be ax^2+bx+c. But Idk what to do about this equation since there are - signs instead.
a is +3
b is -1
c is -16
To solve the quadratic equation 3x^2 - x - 16 = 0 using the quadratic formula, first, let's identify the coefficients of the equation.
The quadratic formula states that for an equation in the form ax^2 + bx + c = 0, the solutions for x can be found using the formula:
x = (-b ± √(b^2 - 4ac)) / (2a)
In the equation 3x^2 - x - 16 = 0, the coefficient of x^2 is 3 (a), the coefficient of x is -1 (b), and the constant term is -16 (c).
Plugging these values into the quadratic formula, we get:
x = (-(-1) ± √((-1)^2 - 4 * 3 * (-16))) / (2 * 3)
Simplifying further:
x = (1 ± √(1 + 192)) / 6
Now, let's simplify the expression inside the square root:
x = (1 ± √(193)) / 6
Therefore, the solutions to the quadratic equation 3x^2 - x - 16 = 0, using the quadratic formula, are:
x = (1 + √193) / 6
and
x = (1 - √193) / 6