# Imagine a landing carft approaching the surface of Callisto, one of Jupiture's moons. If the engine provides an upward force (thrust) of 3260 N, the craft descends at constant speed; if the engine provides only 2200 N the craft accelerates downward at .39 m/s^2. a) What is the weight of the landing craft in the vicinity of Callisto's surface? b) what is the mass of the craft? c)What is the magnutide of the free-fall acceleration near the surface of Callisto?

I need help. I can't figure out what to do I am confused. a) is 3260 N b) is 2.7 X10^3 kg c) is 1.2m/s but I don't know how to get these answers.

a) Since 3260 N thrust provides a constant velocity (presumably they are talking about near Callisto's surface), then it equals the weight. W = 3260 N

b) The mass can be obtained from

m = F/a, where F is the net force when a = 0.39 m/s^2. F = 3260 - 2200 = 1060 N in that siuation, so m = 1060/.39 = 2.72*10^3 kg

c) Free-fall acceleration = W/m

## WOOOH I LIKE TACOS

## To get the free-fall acceleration near the surface of Callisto (c), we need to divide the weight (a) by the mass (b).

c) Free-fall acceleration = Weight / Mass

Given that the weight (a) is 3260 N and the mass (b) is 2.72 x 10^3 kg, we can substitute the values into the equation:

c) Free-fall acceleration = 3260 N / 2.72 x 10^3 kg

Simplifying the equation gives us:

c) Free-fall acceleration = 1.2 m/s^2

Therefore, the magnitude of the free-fall acceleration near the surface of Callisto is 1.2 m/s^2.