What is the pOH of a solution with [OH-] = 2.0 10-2?
pOH = -log(OH^-)
To find the pOH of a solution, you need to first determine the concentration of hydroxide ions ([OH-]). In this case, the given concentration of [OH-] is 2.0 x 10^-2.
The pOH is calculated using the formula:
pOH = -log[OH-]
Substituting the given concentration:
pOH = -log(2.0 x 10^-2)
To evaluate the logarithm, you can use the logarithmic function on a calculator or follow these steps:
1. Take the logarithm of 2.0 x 10^-2:
log(2.0 x 10^-2)
2. Simplify the calculation:
log(2.0) + log(10^-2)
3. Apply the logarithm rules to simplify further:
log(2.0) - 2
4. Calculate the antilogarithm (inverse logarithm) of the simplified expression:
10^(log(2.0) - 2)
Using a calculator for the values inside parentheses, you will find that log(2.0) ≈ 0.3010. Substituting this in the expression, you get:
10^(0.3010 - 2)
Evaluating 10^(0.3010 - 2), you will find that it is approximately 0.0501187.
Therefore, the pOH of a solution with [OH-] = 2.0 x 10^-2 is approximately 1.30.