a pitcher throws a 0.145-kg baseball at a velocity of 30.0 m/s. how much kinetic energy does the ball have?
CORRECTION:
KE = 0.0725*(30)^2 = 65.25 Joules.
a pitcher throws a 0.145-kg baseball at a velocity of 30.0 m/s. how much kinetic energy does the ball have?
To calculate the kinetic energy of an object, you can use the equation:
Kinetic energy (KE) = (1/2) * mass * velocity^2
Now, let's plug in the given values:
mass = 0.145 kg
velocity = 30.0 m/s
Substituting the values into the equation, we have:
KE = (1/2) * 0.145 kg * (30.0 m/s)^2
First, calculate the square of the velocity:
(30.0 m/s)^2 = 900 m^2/s^2
Now, substitute the squared velocity into the equation:
KE = (1/2) * 0.145 kg * 900 m^2/s^2
Next, multiply the mass and the squared velocity:
KE = 0.5 * 0.145 kg * 900 m^2/s^2
Now, multiply 0.5 by 0.145 kg:
KE = 0.0725 kg * 900 m^2/s^2
Finally, multiply 0.0725 kg by 900 m^2/s^2:
KE ≈ 65.3 J (joules)
So, the baseball has approximately 65.3 joules of kinetic energy.