The length of a sude of a square is 3x+2. What is the area of this square in terms of x
(3x+2)(3x+2) = 9 x^2 + 12 x + 4
Thank you that's what i thought but i needed somebody to check it
rar
To find the area of a square, we need to square the length of one of its sides. In this case, the length of one side of the square is 3x+2.
To find the area in terms of x, we simply need to square 3x+2.
So, the area of the square is:
(3x+2)^2
Expanding this expression, we get:
(3x+2)(3x+2)
To simplify this expression, we can use the FOIL method (First, Outer, Inner, Last):
(3x * 3x) + (3x * 2) + (2 * 3x) + (2 * 2)
Simplifying further, we have:
9x^2 + 6x + 6x + 4
Combining like terms, we get:
9x^2 + 12x + 4
Therefore, in terms of x, the area of the square is 9x^2 + 12x + 4.