a body of mass 5kg is thrown vertically upwards with a speed of 10m/s. what is its kinetic energy when its thrown? find its potential energy when it reaches at the highest point. also find the maximum height attained by the body[g=10m/s]
A body of mass 6kg was pull by a force of 15N find the acceleration give to a body
To find the kinetic energy (KE) of the body when it is thrown upward, we can use the formula:
KE = (1/2) * mass * velocity²
Given:
Mass (m) = 5 kg
Velocity (v) = 10 m/s
Plugging in the values, we get:
KE = (1/2) * 5 kg * (10 m/s)²
= (1/2) * 5 kg * 100 m²/s²
= 250 J (Joules)
Therefore, the kinetic energy of the body when it is thrown upward is 250 Joules.
To find the potential energy (PE) of the body when it reaches the highest point, we can use the equation:
PE = mass * gravitational acceleration * height
Given:
Mass (m) = 5 kg
Gravitational acceleration (g) = 10 m/s²
Plugging in these values, we can calculate the potential energy:
PE = 5 kg * 10 m/s² * height
= 50 kg·m²/s² * height
= 50 J * height
Since the potential energy at the highest point is equal to the kinetic energy when it was thrown (due to the conservation of energy), we can substitute the values:
250 J = 50 J * height
Dividing both sides by 50 J:
height = 250 J / 50 J
= 5 m
Therefore, the maximum height attained by the body is 5 meters.