A young boy swings a yo-yo horizontally above his head at an angular acceleration of 0.42 rad/s2. If the string is 0.55 m long, what is the tangential acceleration of the yo-yo?
R*(angular acceleration) = 0.231 m/s^2
To find the tangential acceleration of the yo-yo, we can use the formula:
Tangential acceleration = Radius of rotation x Angular acceleration
Given:
Angular acceleration (α) = 0.42 rad/s²
Radius of rotation (r) = 0.55 m
Plugging in the values, we can calculate the tangential acceleration:
Tangential acceleration = 0.55 m x 0.42 rad/s²
Tangential acceleration ≈ 0.231 m/s²
Therefore, the tangential acceleration of the yo-yo is approximately 0.231 m/s².
To find the tangential acceleration of the yo-yo, we need to use the formula for tangential acceleration:
Tangential acceleration = Angular acceleration * Radius
In this case, the angular acceleration is given as 0.42 rad/s^2 and the radius (length of the string) is given as 0.55 m.
So, the tangential acceleration of the yo-yo is:
Tangential acceleration = 0.42 rad/s^2 * 0.55 m
Tangential acceleration = 0.231 m/s^2
Therefore, the tangential acceleration of the yo-yo is 0.231 m/s^2.