Is this the correct equatioin for the reaction of cyclohexene with MnO4- ?
C6H10 + MnO4- ----> C6H10(OH)2 + MnO2
Yes.
To determine if the given equation is correct for the reaction of cyclohexene with MnO4-, we need to balance the equation by ensuring that the same number of each type of atom appears on both sides of the equation.
First, let's count the atoms on each side of the equation:
Left side (reactants): C6H10 + MnO4-
Right side (products): C6H10(OH)2 + MnO2
On the reactant side, we have:
- Carbon (C): 6 atoms
- Hydrogen (H): 10 atoms
- Manganese (Mn): 1 atom
- Oxygen (O): 4 atoms
On the product side, we have:
- Carbon (C): 6 atoms
- Hydrogen (H): 14 atoms (2 in each OH group)
- Oxygen (O): 2 atoms (from C6H10(OH)2) and 2 atoms (from MnO2)
- Manganese (Mn): 1 atom
To balance the equation, we need to adjust the coefficients in front of each compound.
The balanced equation for the reaction of cyclohexene with MnO4- is:
C6H10 + 3MnO4- ----> C6H10(OH)2 + 3MnO2
By balancing the equation, we ensure that both sides have an equal number of atoms for each element.
Note: It is crucial to write the correct coefficients in front of each compound to balance the equation properly.