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Write the balanced chemical equation for each of these reactions. Include phases. When aqueous sodium hydroxide is added to a solution containing lead(II) nitrate, a solid precipitate forms. However, when additional aqueous hydroxide is added the precipitate redissolves forming a soluble [Pb(OH)4]2–(aq) complex ion.

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15 answers

  1. Pb(OH)2 (s) + 2NaOH (aq) <--> [Pb(OH)4]^2- + 2Na^+ (aq)

    Don't include the "-" in NaOH

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  2. Not correct on sapling

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  3. 2NaOH(aq)+Pb(NO3)2(aq)--->Pb(OH)2(s)+2NaNO3(aq)

    Pb(OH)2(s)+2OH^-(aq)--->[Pb(OH)4]^2-(aq)

    just saw the answer on sapling.

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  4. I had the exact same question, but the when I tried the second equation, it was wrong.

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  5. Same as Sarah

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  6. You forgot the 2Na+(aq) ions as products of the second reaction.

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  7. You have to put " Pb(OH)4(aq) " in square brackets... [Pb(OH)4]2–(aq)

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  8. The answer for the second equation input is

    Pb(OH)2 (s) + 2 NaOH^- (aq) --> [Pb(OH)4]^2- (aq) + 2 Na^+ (aq)

    This part of the problem annoyed the hell out of me before I actually got it.

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  9. Ole ole Pumas!
    The answer in right

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  10. Na2Pb(OH)H(aq)

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  11. Ok, here is the final answer that worked for mines on Sapling
    1: 2NaOH(aq) + Pb(NO3)2(aq) --> Pb(OH)2(s) + 2NaNO3(aq)
    2: Pb(OH)2(s) + 2OH^-(aq) --> [Pb(OH)4]^2-(aq)

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  12. 2NaOH(aq) + Pb(NO3)2(aq)-----> Pb(OH)2(s) + 2NaNO3(aq)
    **** for Pb(NO3)2 the 2 does not mean to square it you have to put it in the bottom corner as well as Pb(OH)2 the 2 does not mean to square it has to be put in the bottom corner

    Pb(OH)2(s) +2OH-(aq)----->[Pb(OH)4]2-(aq)

    ****for Pb(OH)2 the 2 does not mean to square it you have to put it in the bottom corner
    ****in [Pb(OH)4]2- the 2- IS SQUARED and the 4 is in the bottom corner

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  13. I can confirm Tamerra's answer.
    2NaOH(aq)+Pb(NO3)2(aq)--->Pb(OH)2(s)+2NaNO3(aq)

    Pb(OH)2(s)+2OH^-(aq)--->[Pb(OH)4]^2-(aq)

    is the correct answer on Sapling.

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  14. second equation is

    Pb(OH)2(s)+2OH^-(aq)<---> [Pb(OH)4]^2-(aq)

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  15. 2NaOH(aq) + Pb(NO3)2(aq) ==> Pb(OH)2(s) + 2NaNO3(aq)

    Pb(OH)2(s) + 2NaOH(aq) ==> Na2Pb(OH)4(aq)

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