together, steve and tom sold 130 raffle tickets for their school. steve sold 14 more than three times as many tickets as tom. how many tickets did each boy sell
To find out how many tickets each boy sold, let's break down the information given step by step.
Let's assume Tom sold x tickets.
According to the problem, Steve sold 14 more than three times the number of tickets Tom sold. That means Steve sold (3x + 14) tickets.
The total number of tickets sold by both Steve and Tom is given as 130. So, we can set up an equation:
Tom's tickets + Steve's tickets = Total tickets
x + (3x + 14) = 130
Now we can solve the equation to find the value of x.
Combining like terms, we have:
4x + 14 = 130
To isolate x, we subtract 14 from both sides of the equation:
4x = 130 - 14
4x = 116
Finally, we divide both sides by 4 to solve for x:
x = 116 / 4
x = 29
So, Tom sold 29 tickets.
Now, to find out how many tickets Steve sold, we substitute the value of x back into the equation:
Steve's tickets = 3x + 14
Steve's tickets = 3 * 29 + 14
Steve's tickets = 87 + 14
Steve's tickets = 101
Therefore, Steve sold 101 tickets.
To summarize:
Tom sold 29 tickets, and Steve sold 101 tickets.
T = Tom
T + 3T + 14 = 130
4T = 116
T = ?