Questions LLC
Login
or
Sign Up
Ask a New Question
Mathematics
Trigonometry
Quadrants
what quadrant is this in and please explain... sin theta < 0, cos theta > 0
1 answer
sin -, cos+
sin is - in II, IV
cos is + in I, IV
You can
ask a new question
or
answer this question
.
Related Questions
Julia wants to simplify the term sec^2 theta-1/cot^2 theta+1 in a trigonometric identity that she is proving. Which of the
Simplify the trigonometric expression.
sin^2 theta / 1-cos theta A. 1+cos theta B. sin theta C. 1-sin theta / cos theta D. 1+sin
1. Let (-7, 4) be a point on the terminal side of (theta). Find the exact values of sin(theta), csc(theta), and cot(theta).
2.
Which of the following are trigonometric identities? Select all that apply (there are 3 answers).
A cos^2(theta)=sin^2(theta)-1 B
let theta be an angle of quadrant IV such that sin theta = -8/9 find the exact value of sec theta and cot theta?
Let theta be an angle in quadrant IV such that sin(theta)=-(2)/(5).
Find the exact values of sec(theta) and tan(theta).
Express in functions of theta:
a. sin ( 810- theta) b. cot ( theta - 360) c cos (-180- theta)
If sin(θ)=8/10, 0≤θ≤π/2, then
cos(theta)= tan(theta)= Sec(theta)= Please explain how to do this
1) If x = rcos theta and y = r sin theta, show that partial r / partial x = cos theta and find partial theta / partial x.
2) If z
1. sin^2 theta+cos theta=2 (Hint: Use the Pythagorean identity sin^2 theta+cos theta=1 to replace sin^2 theta in the given