what is the area for h=10,b1=12,b2=14 on a trapiziod
use this 1/2(b1 + b2)
or, better, this:
a = h/2 (b1+b2)
Note: a triangle is just a trapezoid with b1 = 0, so a = 1/2 h (0+b2) = 1/2 bh
a rectangle is just a trapezoid with b1=b2, so a = 1/2 h * (b1+b1) = h*b1
To find the area of a trapezoid, you can use the formula:
Area = (1/2) * (b1 + b2) * h
Where:
- b1 is the length of the first base of the trapezoid
- b2 is the length of the second base of the trapezoid
- h is the height of the trapezoid
In this case, h = 10, b1 = 12, and b2 = 14.
Let's substitute these values into the formula:
Area = (1/2) * (12 + 14) * 10
Next, we simplify the expression inside the parentheses:
Area = (1/2) * 26 * 10
Then, multiply 26 by 10:
Area = 13 * 10
Finally, perform the calculation:
Area = 130
Therefore, for the given values of h = 10, b1 = 12, and b2 = 14, the area of the trapezoid is 130 square units.