# I followed all of your steps and got the first on perfectly. I followed your steps on S=B+1/2Pl and got it down to 2S-2B=Pl. Then for the next step I want to divide everything but I didn't think that would work. So to be honest I have no idea how to go farther than that.

devide everyting by P, that will get it all by itself.

oops!, that will get I all by itself :)

Ok, so it would be 2S/P-2B/P=l ?

ps 2S/P-2B/P=l looks really strange on screen but in words it would be two s over p minus two b over p equals l

2S-2B/P=I is the simple form

alrighty thanks so much :)

hmmm (2S-2B)/P=I is a better way to say it in here, as 2S-2B
_____
P
is the only other way :)

## Great job! You are very close to the final answer. To simplify the expression (2S-2B)/P, we can further divide the numerator by P. This will give us the equation: (2S-2B)/P = I.

In words, this equation represents "two times S minus two times B, all divided by P, equals I."

Remember, when you divide both the numerator and the denominator of a fraction by the same value, it simplifies the expression. So the final step is to divide (2S-2B) by P, which gives us I = (2S-2B)/P.

Keep in mind that when writing mathematical expressions, it is helpful to use parenthesis to clearly indicate the order of operations. So, (2S-2B)/P = I is the preferred way to write it.

I hope this clarifies everything for you. Let me know if you have any further questions!