If 20g of Ca(0H)2 took part in the following reaction, how much CaCl2 would be formed.
Ca(0H)2 + 2HCl to CaCl2 +2H20
20g of Ca(OH)2 is 0.27 moles
Each mole of Ca(OH)2 produces one mole of CaCl2
now go for it...
Ca(0H)2 + 2HCl to CaCl2 +2H20
Each mole of Ca(OH)2 produces one mole of CaCl2
now go for it...