# Hi,

I try to solve this problem with this formula and I can not get the right answer !

F2 = F1 ( R2/R1)

A dentist's chair with a patient in it weighs 1790 N. The output plunger of a hydraulic system begins to lift the chair, when the dentist's foot applies a force of 51.5 N to the input piston. Neglect any height difference between the plunger and the piston. What is the ratio of the radius of the plunger to the radius of the piston?

I got it !

Thanks

121212

I wish someone would have explained how to do this...

## In a hydraulic system, piston 1 has a surface area of 100 cm2, and piston 2 has a surface area of 900 cm2. A force of 150 N is exerted on piston 1 of the hydraulic lift.

What force will be exerted on piston 2?

## 1350 N

## Sure! I'd be happy to explain how to solve this problem.

To find the ratio of the radius of the plunger to the radius of the piston, we can use the formula you mentioned: F2 = F1 (R2/R1).

Let's break down the information given in the problem:

1. The weight of the chair (F2): 1790 N

2. The force applied by the dentist's foot (F1): 51.5 N

Now, let's plug these values into the formula and solve for the ratio (R2/R1):

1790 = 51.5 * (R2/R1)

To isolate (R2/R1) on one side, we divide both sides of the equation by 51.5:

(R2/R1) = 1790 / 51.5

Now, let's calculate the ratio:

(R2/R1) ≈ 34.8

Therefore, the ratio of the radius of the plunger to the radius of the piston is approximately 34.8.

I hope this explanation helps! Let me know if you have any further questions.