Create an image of a landscape, centering around a ball bouncing. The ball should start from a considerable height, which is represented as 3 meters in the image. The ball then bounces on the ground and each time it reaches 60% of its previous height, representing a phenomena of physics. Surroundings should display a serene blue sky, green grass on the ground, and a sun setting in the background. The image should potentially show the fifth bounce about to happen but should not show the bounce itself, as it indicates the question's endpoint.

a ball is dropped from a height of 3m and bounces on the ground . At the top of each bounce, the ball eaches 60% of its previous height. Calculate the total distance travelled by the ball when it hits the ground for the fifth time

Steve Steve answered
12 years ago

This is just finding the sum of the sum of the series

-3 + 6*.6 + 6*.6*.6 + ...
We subtract off the 3 because the ball didn't start from the ground, so its first hop is only the downward part.

a = 6
r = 0.6

S5 = 6 (1-.6^5)/(1-.6)
= 6(2.3056) = 13.8336
S5 - 3 = 10.8336

Check: 3 + 3.6 + 2.16 + 1.296 + 0.7776 = 10.8336

Anonymous Anonymous answered
9 years ago

a ball is droped from a height of 30m above level ground. After each bounce it rises to three quarters of the height from which it fell. find,to the nearest metre, the total distance it has travelled when it strikes the ground for the 7th times

gata gata answered
7 years ago

207.76

Anonymous Anonymous answered
5 years ago

why is a 6?

Clown Bot Clown Bot answered
8 months ago

Well, well, well, what do we have here? A bouncing ball, huh? Sounds like it's going to have quite the adventure! Let's see if we can calculate the total distance traveled.

First, let's take a trip down memory lane and recall what happened during each bounce:

Bounce 1: The ball drops from a height of 3m and reaches 60% of that height, which is 1.8m.
Bounce 2: The ball starts at a height of 1.8m and reaches 60% of that, which is 1.08m.
Bounce 3: The ball begins its journey at 1.08m and reaches 60% of that, which is 0.648m.
Bounce 4: The ball springs back up from 0.648m and reaches 60% of that, which is 0.3888m.

Now, we need to calculate the total distance traveled by adding up the distances covered during each bounce:

Total distance = 3m (drop from the initial height) + 1.8m (first bounce) + 1.08m (second bounce) + 0.648m (third bounce) + 0.3888m (fourth bounce)

After doing some math, we find that the total distance traveled by the ball when it hits the ground for the fifth time is approximately 7.9168 meters.

Well, there you have it! The bouncing ball packed its bags, hopped around a bit, and traveled approximately 7.9168 meters in total. Safe travels, ball!

Explain Bot Explain Bot answered
8 months ago

To calculate the total distance traveled by the ball when it hits the ground for the fifth time, we need to determine the distance traveled during each bounce and add them up. Let's break down the problem to find a pattern.

The ball is dropped from a height of 3m, so the first bounce reaches 60% of 3m, which is 1.8m. The ball then rebounds back up to a certain height and falls again.

For each subsequent bounce, the ball reaches 60% of its previous height. So, the second bounce will reach 60% of 1.8m, which is 1.08m. Similarly, the third bounce will reach 60% of 1.08m, which is 0.648m, and so on.

We need to find the total distance traveled when the ball hits the ground for the fifth time. To do that, we add up the heights reached during each bounce.

During the first bounce, the ball travels a distance of 3m (from the initial drop) plus the distance traveled during the ascent and descent of the ball. Since the ball reaches a height of 1.8m during the first bounce, the total distance traveled during the first bounce is twice that distance, or 2 * 1.8m = 3.6m.

Now, let's calculate the total distance traveled during the subsequent bounces:

- Second bounce: The height reached is 60% of 1.8m, which is 1.08m. The total distance traveled during the second bounce is twice that distance, or 2 * 1.08m = 2.16m.

- Third bounce: The height reached is 60% of 1.08m, which is 0.648m. The total distance traveled during the third bounce is twice that distance, or 2 * 0.648m = 1.296m.

- Fourth bounce: The height reached is 60% of 0.648m, which is 0.3888m. The total distance traveled during the fourth bounce is twice that distance, or 2 * 0.3888m = 0.7776m.

- Fifth bounce: The height reached is 60% of 0.3888m, which is 0.2333m (rounded to 4 decimal places). The total distance traveled during the fifth bounce is twice that distance, or 2 * 0.2333m = 0.4666m (rounded to 4 decimal places).

To find the total distance traveled by the ball when it hits the ground for the fifth time, we add up all the distances traveled during each bounce:

3.6m + 2.16m + 1.296m + 0.7776m + 0.4666m = 8.2992m

Therefore, the total distance traveled by the ball when it hits the ground for the fifth time is approximately 8.2992 meters.

🤔 🤔 Ask a New Question 🤔 🤔