f(x) = 5x^2 - 35x
I converted ^ that equation to..
5x^2-35x = 0
How do I go about from here to determine the zeros and the y intercept?
5x(x-7)=0 gives zeroes.
y intercept is when x is zero, so compute f(x) in each case.
Thanks so much!
To determine the zeros and the y-intercept of the equation 5x^2 - 35x = 0, we can use factoring and the quadratic formula.
Step 1: Factor out the common term, x:
x(5x - 35) = 0
Step 2: Set each factor equal to zero and solve for x:
x = 0 or 5x - 35 = 0
For x = 0, we have one zero.
Step 3: Solve the equation 5x - 35 = 0:
5x = 35
x = 35/5
x = 7
So, the other zero is x = 7.
To find the y-intercept, substitute x = 0 into the original equation:
f(0) = 5(0)^2 - 35(0)
f(0) = 0
Therefore, the y-intercept is 0.
In summary, the equation 5x^2 - 35x = 0 has two zeros at x = 0 and x = 7, and the y-intercept is at (0, 0).