Write an equation of the line with the given x- and y-intercepts.
x-intercept:8 y-intercept:4
Is 8x+4y+=32 the answer
No, your equation is not the answer. Check it yourself by seeing what y is when x = 0 (the y-intercept point). Your equation gives y = 8, and it should give y = 4.
Solve it by first trying the y = mx + b form, where b is the y-intercept and m is the slope.
y = mx + 4
When y = 0 (the x-intercept), x = 8, so
0 = m*8 + 4
m = -1/2
y = -x/2 + 4
or
x + 2y = 8 is the answer.
You could also write it as
4x + 8y = 32
To find the equation of a line with the given x- and y-intercepts, you can use the slope-intercept form of a linear equation, which is y = mx + b. In this form, 'm' represents the slope of the line, and 'b' represents the y-coordinate of the y-intercept.
First, let's find the slope (m) using the given intercepts:
The x-intercept is the point (8, 0), and the y-intercept is the point (0, 4). We can use the slope formula:
m = (y2 - y1) / (x2 - x1)
m = (4 - 0) / (0 - 8)
m = 4 / -8
m = -1/2
Now, substitute the slope (m) and the y-intercept (b) into the slope-intercept form:
y = mx + b
y = (-1/2)x + 4
So, the equation of the line with the given x- and y-intercepts is y = (-1/2)x + 4.
Regarding your provided answer, 8x + 4y = 32, it is not correct because it does not satisfy the given x- and y-intercepts.