A trapezoid has an area of 128in2(inches squared), height of 32in, and one base is 5 inches. What is the length of the other base? How do I figure this?
The area of a trapezoid is H*(b1+b2)/2.
128=32*(5+x)/2
128=16(5+x)
8=5+x
8-5=x
x=3 inches
To find the length of the other base of the trapezoid, we can use the formula for the area of a trapezoid:
Area = (1/2) * (a + b) * h
Where:
- Area is the given area of the trapezoid (128in2)
- a is the length of one base (5 inches)
- b is the length of the other base (unknown)
- h is the height of the trapezoid (32 inches)
Plugging in the values we know:
128 = (1/2) * (5 + b) * 32
Now let's solve the equation step by step:
First, we simplify the equation:
128 = (5 + b) * 16
Next, we can remove the parentheses by distributing the 16:
128 = 80 + 16b
Then, we isolate the variable by subtracting 80 from both sides of the equation:
48 = 16b
Finally, we solve for b by dividing both sides of the equation by 16:
b = 3
Therefore, the length of the other base is 3 inches.