What is the acceleration acting on a grandfather clock's pendulum, of length 0.9m, with a maximum angular displacement of 0.1rad?

What is the total distance traveled by that pendulum in one complete oscillation?

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To find the acceleration acting on a grandfather clock's pendulum, we can use the formula for the acceleration of an object in simple harmonic motion:

a = (ω^2) * x

Where:
a is the acceleration
ω is the angular frequency
x is the displacement

First, we need to find the angular frequency (ω). The formula for angular frequency is:

ω = 2πf

Where:
ω is the angular frequency
f is the frequency of oscillation

Since a grandfather clock typically swings back and forth in a time period of 2 seconds, the frequency (f) is 1/2 Hz.

Substituting the value of frequency into the formula:

ω = 2π * (1/2) = π rad/s

Now we know the angular frequency (ω), the displacement (x), and can calculate the acceleration (a):

a = (π^2) * (0.1) = 0.31 m/s^2

So, the acceleration acting on the grandfather clock's pendulum is 0.31 m/s^2.

To find the total distance traveled by the pendulum in one complete oscillation, we can use the formula:

total distance = 2π * length

Where:
total distance is the distance traveled in one complete oscillation
length is the length of the pendulum

Substituting the given length:

total distance = 2π * 0.9 = 5.65 meters

Therefore, the total distance traveled by the grandfather clock's pendulum in one complete oscillation is 5.65 meters.