# H2SO4+B(OH)3=B2(SO4)3+H2O

3 H2SO4
2 B (OH)3
1 B2(SO4)3
6 H2O

## Now the how and why:

I said I will have x B2(SO4)3 molecules
Then I must have 2x B(OH)3 molecules
I assume I have y H2O molecules
Then I have 2 Y H atoms on the right
but on the left I have 3 x H2SO4 molecules to balance 3 x sulfur on the right
and I have 2 x B(OH)3 molecules on the left to balance B
so
I have 6x + 6x or 12 x H atoms on the left to balance my 2 y H atoms on the right
12 x = 2 y
6 x = y
so I tried x = 1 and y =6 and it balanced

## To balance the chemical equation H2SO4 + B(OH)3 = B2(SO4)3 + H2O, we need to ensure that the number of atoms of each element is the same on both sides of the equation.

Let's start by looking at each element one at a time:

Hydrogen (H):
On the left side, we have 2 hydrogen atoms in H2SO4 and 3 hydrogen atoms in B(OH)3, totaling to 5 hydrogen atoms.
On the right side, we have 2 hydrogen atoms in H2O.
To balance the hydrogen atoms, we need a coefficient of 5 in front of H2O.

Oxygen (O):
On the left side, we have 4 oxygen atoms in H2SO4 and 3 oxygen atoms in B(OH)3, totaling to 7 oxygen atoms.
On the right side, we have 12 oxygen atoms in B2(SO4)3 and 1 oxygen atom in H2O, totaling to 13 oxygen atoms.
To balance the oxygen atoms, we need a coefficient of 7 in front of H2O.

Sulfur (S):
On the left side, we have 1 sulfur atom in H2SO4.
On the right side, we have 3 sulfur atoms in B2(SO4)3.
To balance the sulfur atoms, we need a coefficient of 3 in front of B(OH)3.

Boron (B):
On the left side, we have 1 boron atom in B(OH)3.
On the right side, we have 2 boron atoms in B2(SO4)3.
To balance the boron atoms, we need a coefficient of 2 in front of H2SO4.

After balancing all the elements, the balanced chemical equation is:
2H2SO4 + 3B(OH)3 = B2(SO4)3 + 6H2O

## The chemical equation you provided represents a double displacement reaction between sulfuric acid (H2SO4) and boric acid (B(OH)3). The reaction results in the formation of boron sulfate (B2(SO4)3) and water (H2O).

To understand how this reaction proceeds and calculate the balanced equation, we need to follow a few steps:

Step 1: Identify the chemical formula of each compound involved:
- Sulfuric acid: H2SO4
- Boric acid: B(OH)3
- Boron sulfate: B2(SO4)3
- Water: H2O

Step 2: Determine the cations and anions in each compound:
- Sulfuric acid (H2SO4) dissociates into the cation H+ and the polyatomic anion SO4^2-.
- Boric acid (B(OH)3) dissociates into the cation B(OH)3 and does not have an anion since it is a weak acid.
- Boron sulfate (B2(SO4)3) consists of the cation B3+ and the polyatomic anion SO4^2-.
- Water (H2O) dissociates into the cation H+ and the anion OH- (hydroxide ion).

Step 3: Determine the possible products of the reaction:
To exchange ions, the cations from one compound join the anions from the other compound. So, in this case, the cations B3+ from boric acid will combine with the anions SO4^2- from sulfuric acid, while the cations H+ from sulfuric acid will combine with the anions OH- from water.

Step 4: Write the balanced chemical equation:
B2(SO4)3 + 6H2O

Note that the coefficient in front of the molecule or ion represents the number of those molecules or ions in the reaction.

So, the balanced chemical equation for the reaction between sulfuric acid and boric acid is:
2H2SO4 + 3B(OH)3 → B2(SO4)3 + 6H2O