The ordered pairs in each exercise are for the same direct variation.

Find the missing value.

(3,2) and (6,y)

I don't know how to find the missing value ..

yes, 4

To find the missing value in a direct variation, you can use the concept of ratios. In a direct variation, the ratio between the x-values and the y-values remains constant.

In this case, the given ordered pairs are (3,2) and (6,y). Since these pairs represent a direct variation, we can set up a ratio using the x-values and the y-values:

x1 / y1 = x2 / y2

Substituting the given values from the ordered pairs:

3 / 2 = 6 / y

To solve for the missing value, we can cross-multiply:

3y = 12

Now, divide both sides of the equation by 3 to isolate the variable:

y = 4

Therefore, the missing value is y = 4.


well.....yes 4 but what if it was

(5,9), (15,y)

Assuming that "direct variation" means that the second number of each pair is a certain fixed ratio to the first number, then

3/2 = 6/y
3y = 12
y = ?